Implement Ranks — gapped fractional ordering

Pure ordering math: append at max+1024, head-insert at min−1024,
midpoint insertion with precision-exhaustion detection (nil on ties and
rounding onto an endpoint), renumbering to whole multiples of 1024, the
shared display-order tie-break (order, then folder name), and
tombstone-excluding overloads. 18 tests.

Claude-Session: https://claude.ai/code/session_018BjQRYBR6jQja3jCRi5S3A
This commit is contained in:
2026-07-26 15:12:26 -04:00
parent 9472198848
commit 4e016fe8fe
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import Foundation
/// Pure gapped-fractional-ordering math: append, insert, midpoint, and the
/// renumber target, plus the display-order tie-break rule shared by the
/// loader and the writer. No filesystem or model dependency see
/// DESIGN/01-storage-format.md § Ordering, Deletion.
enum Ranks: Sendable {
/// Gap between successive ranks on append/head-insert, and the multiple
/// used by `renumbered(count:)`.
private static let gap: Double = 1024
// MARK: - Append / insert
/// Rank for a new item appended after all visible siblings.
/// An empty lane's first item lands at `1024` (the board convention).
static func append(toVisible orders: some Sequence<Double>) -> Double {
(orders.max() ?? 0) + gap
}
/// Rank for a new item inserted before all visible siblings.
/// An empty lane's first item lands at `1024` (the board convention).
static func insertAtHead(ofVisible orders: some Sequence<Double>) -> Double {
guard let minOrder = orders.min() else { return gap }
return minOrder - gap
}
/// Rank strictly between `a` and `b`, or `nil` if no `Double` is
/// representable between them including when `a == b` (a duplicate
/// order, the tie case). Never returns a value min(a, b) or
/// max(a, b).
static func midpoint(between a: Double, and b: Double) -> Double? {
let lower = min(a, b)
let upper = max(a, b)
guard lower < upper else { return nil }
let mid = lower + (upper - lower) / 2
guard mid > lower, mid < upper else { return nil }
return mid
}
/// `count` fresh ranks, whole multiples of 1024 in ascending order
/// (1024, 2048, ) the renumber target when midpoint precision is
/// exhausted. Deterministic by construction; the writer applies these,
/// in order, to the current visible siblings in display order.
static func renumbered(count: Int) -> [Double] {
guard count > 0 else { return [] }
return (1...count).map { Double($0) * gap }
}
// MARK: - Display order
/// Ascending display order: primary key `order`, ties broken by folder
/// name (lexicographic) for deterministic rendering. Shared by the
/// loader and the writer so both apply the same tie-break rule.
static func isOrderedForDisplay<T>(
_ lhs: T, before rhs: T,
order: (T) -> Double, name: (T) -> String
) -> Bool {
let lhsOrder = order(lhs)
let rhsOrder = order(rhs)
return lhsOrder != rhsOrder ? lhsOrder < rhsOrder : name(lhs) < name(rhs)
}
/// Sorts siblings into display order ascending `order`, ties broken by
/// folder name.
static func sortedForDisplay<T>(
_ items: [T],
order: (T) -> Double,
name: (T) -> String
) -> [T] {
items.sorted { isOrderedForDisplay($0, before: $1, order: order, name: name) }
}
// MARK: - Tombstone exclusion
/// `append(toVisible:)`, ignoring tombstoned siblings. Tombstones are
/// inert to ordering appends operate on visible siblings only.
static func append(toVisible items: some Sequence<(order: Double, isDeleted: Bool)>) -> Double {
append(toVisible: items.filter { !$0.isDeleted }.map { $0.order })
}
/// `insertAtHead(ofVisible:)`, ignoring tombstoned siblings. Tombstones
/// are inert to ordering inserts operate on visible siblings only.
static func insertAtHead(ofVisible items: some Sequence<(order: Double, isDeleted: Bool)>) -> Double {
insertAtHead(ofVisible: items.filter { !$0.isDeleted }.map { $0.order })
}
}
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import Testing
@testable import Kanban
struct RanksTests {
// MARK: - Append
@Test func appendOnEmptyLaneReturnsBoardConvention() {
#expect(Ranks.append(toVisible: [Double]()) == 1024)
}
@Test func appendReturnsMaxPlusGap() {
#expect(Ranks.append(toVisible: [1024, 2048, 512]) == 3072)
}
// MARK: - Insert at head
@Test func insertAtHeadOnEmptyLaneReturnsBoardConvention() {
#expect(Ranks.insertAtHead(ofVisible: [Double]()) == 1024)
}
@Test func insertAtHeadReturnsMinMinusGap() {
#expect(Ranks.insertAtHead(ofVisible: [1024, 2048, 512]) == -512)
}
// MARK: - Midpoint
@Test func midpointBetweenDistinctValuesIsStrictlyBetween() throws {
let mid = try #require(Ranks.midpoint(between: 1024, and: 2048))
#expect(mid == 1536)
#expect(mid > 1024 && mid < 2048)
}
@Test func midpointIsOrderIndependent() {
let forward = Ranks.midpoint(between: 1024, and: 2048)
let reversed = Ranks.midpoint(between: 2048, and: 1024)
#expect(forward == reversed)
}
@Test func midpointBetweenEqualValuesReturnsNil() {
#expect(Ranks.midpoint(between: 42, and: 42) == nil)
}
@Test func midpointNeverEscapesTheOpenInterval() {
// Values close enough that a naive (a+b)/2 could round to one of the
// endpoints; the result (if any) must stay strictly inside.
let a = 1.0
let b = 1.0.nextUp.nextUp.nextUp
if let mid = Ranks.midpoint(between: a, and: b) {
#expect(mid > a && mid < b)
}
}
// MARK: - Renumbered
@Test func renumberedProducesWholeMultiplesOf1024() {
#expect(Ranks.renumbered(count: 4) == [1024, 2048, 3072, 4096])
}
@Test func renumberedWithZeroCountIsEmpty() {
#expect(Ranks.renumbered(count: 0) == [])
}
// MARK: - Display order / tie-break
@Test func sortedForDisplayOrdersAscendingByRank() {
let items: [(order: Double, name: String)] = [
(order: 3072, name: "c-card"),
(order: 1024, name: "a-card"),
(order: 2048, name: "b-card"),
]
let sorted = Ranks.sortedForDisplay(items, order: { $0.order }, name: { $0.name })
#expect(sorted.map { $0.name } == ["a-card", "b-card", "c-card"])
}
@Test func sortedForDisplayBreaksTiesByFolderName() {
let items: [(order: Double, name: String)] = [
(order: 1024, name: "zzz-uuid"),
(order: 1024, name: "aaa-uuid"),
(order: 1024, name: "mmm-uuid"),
]
let sorted = Ranks.sortedForDisplay(items, order: { $0.order }, name: { $0.name })
#expect(sorted.map { $0.name } == ["aaa-uuid", "mmm-uuid", "zzz-uuid"])
}
@Test func isOrderedForDisplayMatchesSortedForDisplay() {
let a: (order: Double, name: String) = (order: 1024, name: "aaa")
let b: (order: Double, name: String) = (order: 1024, name: "bbb")
#expect(Ranks.isOrderedForDisplay(a, before: b, order: { $0.order }, name: { $0.name }))
#expect(!Ranks.isOrderedForDisplay(b, before: a, order: { $0.order }, name: { $0.name }))
}
// MARK: - Tombstone exclusion
@Test func appendIgnoresTombstonedSiblings() {
let items: [(order: Double, isDeleted: Bool)] = [
(order: 1024, isDeleted: false),
(order: 9999, isDeleted: true),
(order: 2048, isDeleted: false),
]
#expect(Ranks.append(toVisible: items) == 3072)
}
@Test func insertAtHeadIgnoresTombstonedSiblings() {
let items: [(order: Double, isDeleted: Bool)] = [
(order: 1024, isDeleted: false),
(order: -9999, isDeleted: true),
(order: 2048, isDeleted: false),
]
#expect(Ranks.insertAtHead(ofVisible: items) == 0)
}
@Test func appendWithAllSiblingsTombstonedReturnsBoardConvention() {
let items: [(order: Double, isDeleted: Bool)] = [
(order: 1024, isDeleted: true),
(order: 2048, isDeleted: true),
]
#expect(Ranks.append(toVisible: items) == 1024)
}
@Test func insertAtHeadWithAllSiblingsTombstonedReturnsBoardConvention() {
let items: [(order: Double, isDeleted: Bool)] = [
(order: 1024, isDeleted: true),
(order: 2048, isDeleted: true),
]
#expect(Ranks.insertAtHead(ofVisible: items) == 1024)
}
// MARK: - Precision exhaustion renumber, deterministically
@Test func precisionExhaustionThenRenumberIsDeterministic() {
func runScenario() -> (iterations: Int, renumbered: [Double]) {
let lower = 1024.0
var upper = 2048.0
var iterations = 0
let iterationCap = 4000
while iterations < iterationCap, let mid = Ranks.midpoint(between: lower, and: upper) {
upper = mid
iterations += 1
}
return (iterations, Ranks.renumbered(count: 5))
}
let first = runScenario()
let second = runScenario()
// Precision must actually have been exhausted, not just hit the cap.
#expect(first.iterations > 0)
#expect(first.iterations < 4000)
// Same scenario, run twice, must produce bit-identical results.
#expect(first.iterations == second.iterations)
#expect(first.renumbered == second.renumbered)
// Renumbering yields clean whole multiples of 1024.
#expect(first.renumbered == [1024, 2048, 3072, 4096, 5120])
}
}